 Key Wheeling in a Trifecta Bet
Key-wheeling in a trifecta bet means selecting a key horse in a fixed
position, usually first, and
wheeling any number of other horses in multiple
combinations to finish in the remaining positions, usually second and third.
If the 1 is key-wheeled with the 2, 3, and 5, the combinations of 1-2-3,
1-2-5, 1-3-2, 1-3-5, 1-5-2, and 1-5-3 are covered. As long as the 1 is the
winner and any combination of the numbers 2, 3, and 5 are second and third,
the key-wheeled wager is a winner. The more numbers used with the
key-wheeled selection, the greater the number of possibilities covered.
However, the more numbers used, the greater the cost to cover the wager.
|
|
|
|
2 |
2 |
$1
($2) |
$2
($4) |
3 |
6 |
$1
($2) |
$6
($12) |
4 |
12 |
$1
($2) |
$12
($24) |
5 |
20 |
$1
($2) |
$20
($40) |
6 |
30 |
$1
($2) |
$30
($60) |
7 |
42 |
$1
($2) |
$42
($84) |
8 |
56 |
$1
($2) |
$56
($112) |
9 |
72 |
$1
($2) |
$72
($144) |
10 |
90 |
$1
($2) |
$90
($180) |
11 |
110 |
$1
($2) |
$110
($220) |
12 |
132 |
$1
($2) |
$132
($264) |
13 |
156 |
$1
($2) |
$156
($312) |
A simple rule to remember to compute the cost
of a key-wheeled trifecta wager would be as follows:
the number of horses to be boxed with the keyed selection MULTIPLIED by the next lowest number MULTIPLIED by the dollar amount of the wager. EXAMPLE: A key-wheeled trifecta using 4 choices with the key-wheeled selection for $2
would be computed 4 (the number of horses boxed with the key-wheeled selection) x 3 (next lowest number) x 2 (dollar amount of wager) = $24.
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